About Council of Scientific and Industrial Research Recruitment 2026
Council of Scientific and Industrial Research has officially announced the recruitment process for Joint CSIR UGC Test for JRF & NET June 2019. Selected candidates will be posted across All India.
Candidates can apply online through the official website. Interested and eligible candidates are encouraged to submit their applications before the deadline.
Key highlights: the application fee varies by category (see fee table below). Candidates are advised to carefully review the eligibility criteria and other requirements before applying.
Key Highlights
Vacancy Details
| Post Name | Vacancies | Qualification | Salary |
|---|---|---|---|
| Junior Research Fellowship (JRF) | — | M.Sc / Equivalent Degree with 55% Marks for General / OBC Candidates. For SC / ST and PH Candidates: 50% Marks. Integrated Course and B.E/ B.Tech / B.Pharma and MBBS Candidates Are Also Eligible. | — |
| National Eligibility Test (NET) for Lectureship | — | M.Sc / Equivalent Degree with 55% Marks for General / OBC Candidates. For SC / ST and PH Candidates: 50% Marks. Integrated Course and B.E/ B.Tech / B.Pharma and MBBS Candidates Are Also Eligible. | — |
Important Dates
| Application Begin | 25/02/2019 |
| Last Date Fee Deposit | 22/03/2019 |
| Last Date Complete Form | 22/03/2019 |
| Exam Held On | 16/06/2019 |
| Admit Card Available | 05/06/2019 |
| Answer Key Available | 05/07/2019 |
| Result Available | 16/08/2019 |
| Marks Available | 24/08/2019 |
Application Fee
| General | 1000/- |
| OBC | 500/- |
| SC | 250/- |
| ST | 250/- |
| PH / / / PwD | 250/- |
Age Limit & Relaxation
| Maximum Age | 28 Years Years |
| Age Cutoff Date | 01/01/2019 |
* Age relaxation is applicable as per government rules for reserved categories.
Educational Qualification & Eligibility
M.Sc / Equivalent Degree with 55% Marks for General / OBC Candidates. For SC / ST and PH Candidates: 50% Marks. Integrated Course and B.E/ B.Tech / B.Pharma and MBBS Candidates Are Also Eligible.
Documents Required
* Candidates must carry original documents for verification at the time of interview / document verification.
How To Apply
Visit the official website of Council of Scientific and Industrial Research — https://www.sarkariresult.com.
Read the official notification carefully and check your eligibility.
Click on the "Apply Online" / "Registration" link for Joint CSIR UGC Test for JRF & NET June 2019.
Complete the registration by providing a valid email ID and mobile number.
Fill in all required details: personal information, educational qualifications, work experience (if applicable), and address.
Upload scanned copies of your photograph (passport size), signature, and required documents as per the specifications.
Pay the application fee online through the available payment gateway (if applicable).
Review all entered details carefully before final submission.
Submit the application form and take a printout / save a PDF copy for future reference.
Frequently Asked Questions (FAQs)
What is the last date to deposit the application fee for CSIR NET JRF June 2019?
The last date to deposit the application fee is 22 March 2019.
What is the eligibility criteria for General category candidates in CSIR NET JRF June 2019?
General category candidates need an M.Sc / Equivalent Degree with 55% Marks.
What is the application fee for OBC candidates in CSIR NET JRF June 2019?
The application fee for OBC candidates is 500 INR.
What is the maximum age limit for JRF as of 01 January 2019?
The maximum age limit for JRF is 28 years as of 01 January 2019.
Is there any age limit for the NET Lectureship post?
No, there is no age limit for the NET Lectureship post.
When was the CSIR NET JRF June 2019 exam held?
The CSIR NET JRF June 2019 exam was held on 16 June 2019.
When will the admit card for CSIR NET JRF June 2019 be available?
The admit card for CSIR NET JRF June 2019 was available from 05 June 2019.
When will the result for CSIR NET JRF June 2019 be declared?
The result for CSIR NET JRF June 2019 was declared on 16 August 2019.
When will the marks for CSIR NET JRF June 2019 be available?
The marks for CSIR NET JRF June 2019 were available from 24 August 2019.
What is the application fee for SC candidates in CSIR NET JRF June 2019?
The application fee for SC candidates is 250 INR.
What is the application fee for PwD candidates in CSIR NET JRF June 2019?
The application fee for PwD candidates is 250 INR.
Are B.E/B.Tech candidates eligible for CSIR NET JRF June 2019?
Yes, B.E/B.Tech candidates are also eligible for CSIR NET JRF June 2019.
What is the minimum qualification required for CSIR NET JRF June 2019?
The minimum qualification required is an M.Sc / Equivalent Degree with 55% Marks for General / OBC Candidates and 50% Marks for SC / ST and PH Candidates.
How can I pay the application fee for CSIR NET JRF June 2019?
The application fee can be paid through E Challan at any branch of Indian Bank.
Where can I download the result for CSIR NET JRF June 2019?
The result for CSIR NET JRF June 2019 can be downloaded from https://www.sarkariresult.com/download-result.